Symmetric Tree - Mirror Image
Given the root of a binary tree, check whether it is a mirror of itself (i.e., symmetric around its center).
Example 1:
Input: root = [1,2,2,3,4,4,3]
Output: true
Example 2:
Input: root = [1,2,2,null,3,null,3]
Output: false
Constraints:
The number of nodes in the tree is in the range [1, 1000].
-100 <= Node.val <= 100
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public boolean isSymmetric(TreeNode root) {
if(root ==null) return true;
return isMirror(root.left, root.right);
}
public static boolean isMirror(TreeNode root1,TreeNode root2){
if(root1 ==null && root2==null) return true;
if(root1 ==null || root2==null) return false;
return (root1.val == root2.val) && isMirror(root1.left,root2.right) &&
isMirror(root1.right,root2.left);
}
}
Comments
Post a Comment