find the number of trailing zeroes

 Given an integer N, the task is to find the number of trailing zeroes in the binary representation of the given number.


Input 1: N = 12

Output 1: 2

Explanation 1: The binary representation of the number 13 is “1100”. Therefore, there are two trailing zeros in the 12.


Input 2: -56

Output 2: 3


Approach 1 : Use Inbuilt function

int trailingZeroCount = Integer.numberOfTrailingZeros(n); 

Aprroach 2:


public class codefile{
    static int solve(int n){
      // Method to count the number of trailing zeros in the binary representation of 'n'
       
        // Initialize count to 0
        int count = 0;

        // Loop to check each bit from the right (Least Significant Bit)
        // Use 'n & 1' to check if the current bit is 0 (last bit)
        // Shift the number to the right using >>> (unsigned right shift) to process the next bit
        while ((n & 1) == 0) {  // If the last bit is 0, continue
            count++;              // Increment count for each trailing zero
            n = n >>> 1;          // Perform an unsigned right shift to move to the next bit
        }

        // Return the total number of trailing zeros found
        return count;
    }
}


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